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10800 C of electricity passed through th...

`10800 C` of electricity passed through the electrolyte deposited `2.977g` of metal with atomic mass `106.4 g mol^(-1)`. The charge on the metal cation is

A

`+4`

B

`+3`

C

`+2`

D

`+1`

Text Solution

Verified by Experts

The correct Answer is:
A
A/c. , to Faraday's law , `W = (E xxi xx t)/(96500)`
`therefore E = (2.97 xx 96500)/(10800) = 26.6`
`therefore` Valency = `("At. Mass")/("E.mass") = (106.4)/(26.6) = 4`
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