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The emf of the cell in which the followi...

The emf of the cell in which the following reactions,
`Zn(s)+Ni^(2+) (0.1M) rarr Zn^(2+) (1.0 M) + Ni(s)` occurs, is found to 0.5105 V at 298 K. The standard emf of the cell is :

A

`0.540` V

B

`0.4810` V

C

`0.5696 ` V

D

`0.5105`V

Text Solution

Verified by Experts

The correct Answer is:
D
`E_("cell") = E_("cell")^(@) + (0.0592)/(2) log _(10) ([Ni^(2+)])/([Zn^(2+)])`
`0.5105 = E_("cell")^(@) + (0.0592)/(2) log (1)/(1)`
or `E_("cell")^(@) = 0.5105` V
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