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The E(Ag)^(@) = 0.80 V and E("cell")^(@...

The `E_(Ag)^(@) = 0.80 V ` and `E_("cell")^(@) = 1.20` V , for the cell .
`2 Ag^(+) + Cd to 2 Ag + Cd^(2+) ` , the `E_(Cd)^(o)` is

A

`+0.4` V

B

`-0.4 V `

C

`0.8`

D

`-0.8`

Text Solution

Verified by Experts

The correct Answer is:
B
Reduction at Ag electrode and oxidation of Cd electrode .
`therefore E_(cell)^(@) = E_(Ag^(+)|Ag)^(@) = E_(Cd^(2+) | Cd)^(@)`
`1.2 = 0.8 - E_(Cd^(2+)|Cd)^(@)`
`therefore E_(Cd^(2+)|Cd)^(@) = +0.8 - 1.2 = -0.4` V
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