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The standard Gibbs free energy change (D...

The standard Gibbs free energy change `(DeltaG^(@)" in kJ mol"^(-1))`, in a Daniel cell `(E_("cell")^(@)=1.1 V)`, when 2 moles of `Zn (s)` is oxidized at 298 K, is closest to

A

212 . 30

B

`-212.30`

C

`106.15`

D

`-106.15`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta G = - n F E_(cell) = - 2 xx 96500 xx 1.1 J = - 212.3 kJ` .
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