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The equilibrium constant (K) for the rea...

The equilibrium constant (K) for the reaction
`Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be
[Given, `E_(cell)^(@)=0.46 V`]

A

`K_(c) ` = Antilog 15.6

B

`K_(c) ` = Antilog 2.5

C

`K_(c) = ` Antilog 1.5

D

`K_(c)` = Antilog 12.2

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(cell)^(@) = (0.0592)/(n) log K_(c) therefore 0.46 (0.0592)/(2) log K_(c)`
`therefore log K_(c) = (0.46 xx 2)/(0.0592) = 15.6 therefore K_(c) = Al (15.6)`
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