A galvanic cell is set up from a zinc bar weighing `100g` and `1.0L` of `1.0M CuSO_(4)` solution. How long would the cell run if it is assumed to deliver a steady current of `1.0A. (` Atomic mass of `Zn=65)`.

Options

A. 1.1 hr
B. 46 hr
C. 53.6 hr
D. `24.00` hr

Answer

C

Explanation

100 g Zn ` = (100)/(65)` mole = 1.53 mole
1 L of 1 M `CuSO_(4)` sol contains 1 mole of `CuSO_(4)`
`therefore ` In `Zn + CuSO_(4) to Zn SO_(4) + Cu , CuSO_(4)` is the limiting reagent .
To deposit completely 1 mole of Cu , electricity required `= 2 xx 96500 C`
`t = (Q)/(I) = (2 xx 96500)/(1) "sec " = (2 xx 96500)/( 3600) ` hr = 53.6 hr .