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Consider the following relations for emf...

Consider the following relations for `emf` of a electrochemical cell
(i) emf of cell = (Oxidation potential of anode)-(Reduction potential of cathode)
(ii) emf of cell = (Oxidation potential of anode)+(Reduction potential of cathode)
(iii) emf of cell = (Reduction potential of anode)+(Reduction potential of cathode)
(iv) emf of cell = (Oxidation potential of anode)-(Oxidation potential of cathode)
Which of the above realtions are correct?

A

(iii) and (iv)

B

(i) and (ii)

C

(iii) and (iv)

D

(ii) and (iv)

Text Solution

Verified by Experts

The correct Answer is:
D
EMF of a cell = Reduction potential of cathode - Reduction potential of anode = Reduction potential of cathode + Oxidation of anode = Oxidation potential of anode - Oxidation potential of cathode
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