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The equilibrium constant (K) for the rea...

The equilibrium constant (K) for the reaction
`Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be
[Given, `E_(cell)^(@)=0.46 V`]

A

`K_(C) = AL (15.6)`

B

`K_(C) = AL(2.5)`

C

`K_(C) = AL (1.5)`

D

`K_(C) = AL (12.2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E^(@) = (0.0592)/(n) "log" K_(C)`
`therefore log K_(C) = (E^(@) xx n)/(0.0592) = (0.46 xx 2 )/(0.0592) = 15.6`
`therefore K_(C) = AL (15.6)`
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