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If values of Lambda(0) of NH(4)Cl , NaOH...

If values of `Lambda_(0)` of `NH_(4)Cl , NaOH and NaCl` are 130 , 127 and `109 Omega^(-1) cm^(2) eq^(-1)` respectively . The `Lambda_(NH_(4)OH)^(@)` in `Omega^(-1) cm^(2) eq^(-1)` is

A

456

B

238

C

196

D

22

Text Solution

Verified by Experts

The correct Answer is:
B
`Lambda_(NH_(4)OH)^(@)= Lambda_(NH_(4)Cl)^(@) + Lambda_(NaOH)^(@) - Lambda_(NaCl)^(@)`
`= 130 + 217 - 109`
`= +238 Omega cm^(2) eq^(-1)`
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