The ionic conductance of `Ba^(2+)` and `Cl^(-)` respectively are `127` and `76 Omega^(-1) cm^(2)` at infinite dilution. The equivalent conductance `("in "Omega^(-1) cm^(2))` of `BaCl_(2)` at infinite dilute will be

Options

A. 330
B. 203
C. 139.5
D. 51

Answer

C

Explanation

`Lambda_(m)^(@) (BaC_(2)) = lambda_(0) (Ba^(2+)) + 2lambda_(0) (Cl^(-))`
`Lambda_(eq)^(@) (BaCl_(2)) = (1)/(2) lambda^(@) (Ba^(2+)) + lambda ^(@) (Cl^(-))`
= `((1)/(2) xx 127) + 76 = 139.5 Omega^(-1) cm^(2)`