`Al_(2)O_(3)` is reduced by electrolysis at low potentials and high current. If `4.0 xx 10^(4)` amperes of currernt is passed through molten `Al_(2)O_(3)` for 6 hours, what mass of aluminium is produced? (Assume 100 % current efficiency, At. Mass of `Al = 27 u`)

Options

A. `8.1 xx 10^(4)` g
B. `2.4 xx 10^(5)` g
C. `1.3 xx 10^(4)` g
D. `9.0 xx 10^(3)` g

Answer

A

Explanation

Applying E = `Z xx 96500`
` (27)/(3) = Z = 96500 implies Z = (9)/(96500)`
Now applying the formula , `W = Z xx I xx t`
` W = (9)/(96500) xx 4 xx 10^(4) xx 6 xx 60 = 8.1 xx 10^(4)` g .