Standard reduction potentails of the half reactions are given below:
`F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87`
`Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V`
`Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V`
`I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V`
The strongest oxidizing and reducing agents respectively are:

Options

A. `F_(2)` and `I^(-)`
B. `Br_(2)` and `Cl^(-)`
C. `Cl_(2)` and `Br^(-)`
D. `Cl_(2)` and `I_(2)`

Answer

A

Explanation

More negative value of SRP . Stronger will be the reducing agent thus `I^(-)` is a stronger reducing agent . More positive value of SRP stronger will the oxidising agent thus `F_(2)` is a stronger oxidising agent .