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In a cartain operation 358 g of TiCl(4) ...

In a cartain operation 358 g of `TiCl_(4)` is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. Wt. Ti=48, Mg=24][Hint: `358/190=1.88`]

A

(a)35.38%

B

(b)66.6%

C

(c )100%

D

(d)60%

Text Solution

Verified by Experts

The correct Answer is:
A
`TiCl_(4) + 2M Ti + 2MgCl_(2)`
Initial mole `358/190=1.88 96/24=4`
final mole `0 4-2xx1.88 1.88 2xx1.88`
Weight of Ti obtained`=358/190xx48`
`% "yield"=((32xx100)/(358xx48))/190=35.38 %`
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