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NX is produced by the following step of ...

NX is produced by the following step of reactions
`M + X_(2) rightarrow MX_(2)`
`3MX_(2) + X_(2) rightarrow M_(3)X_(8)`
`M_(3)X_(8) + N_(2)CO_(3) rightarrow NX + CO_(2) + M_(3)O_(4)`
How much M (metal) is consumed to produce 206 gm of NX? (Take at. wt of M = 56, N=23, X = 80]

A

(a)42g

B

(b)56 g

C

(c )`14/3` g

D

(d)`7/4` g

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(M,+,X_(2),rarr,MX_(2)),(MX_(2),+,X_(2),rarr,M_(3)X_(8)),(M_(3)X_(8),+,Na_(2)CO_(3),rarr,NX+CO_(2)+M_(3)O_(4)):}`
mole of `NX=206/103=2`
POAC for `X` Atom:
`{:("No. of X atom in" M_(3)X_(8),,,=,"No. of X Atom in NX"),(8 ["No. of mole of" M_(3)X_(8)],,,=,1 ["No. of mole of NX"]),("No. of mole of" M_(3)X_(8),,,=,[2/8]=1/4 "mole"),("Now POAC for M Atom",,,=,),(3 ["o. of mole of" M_(3)X_(8)],,,=,1xx["No. of Mole of M"]):}`
`:. 3xx1/4=` No. of mole of `M`
weight of `M` atom `=3/4xx56=42 grams`
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