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In the following reaction 2I- + Cr(2)O...

In the following reaction
`2I- + Cr_(2)O_(7)^(2-)+14H^(+) rarr I_(2)+2Cl^(3)+7H_(2)O`
Unbalanced parts are

A

`H^(+)`, `H_(2)O`

B

`Cr_(2)O_(7)^(2-)`, `Cr^(3+)`

C

`I^(-)`, `I_(2)`

D

None of them are balanced

Text Solution

Verified by Experts

The correct Answer is:
C

(`I`) `Cr_(2)O_(7)^(2-)+6e^(-) rarr 2Cr^(3+)`
(`II`) `2I^(-) rarr I_(2)+2e^(-)`
To balance electron (`II`) is to be multiplied by (`3`). Thus,
`underline(6I)^(-)+Cr_(2)O_(7)^(2-)+14H^(+) rarr underline(3I)_(2)+2Cr^(3+)+7H_(2)O`
Thus, `I^(-)` and `I_(2)` are not balanced.
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