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In the equation H(2)S+2HNO(3) rarr 2H(2)...

In the equation `H_(2)S+2HNO_(3) rarr 2H_(2)O+2NO_(2)+S` The equivalent weight of hydrogen sulphide is

A

`17`

B

`68`

C

`34`

D

`16`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)S rarr overset(0)(S)+2e`
Equivalent wt. `=(Mol wt.)/(2)=(34)/(2)=17`
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