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0.05 moles of NaHCO(3) will react with h...

`0.05` moles of `NaHCO_(3)` will react with how many equivalent of `Mg(OH)_(2)`?

A

`0.2` equivalent

B

`0.05` equivalent

C

`0.02` equivalent

D

`0.01` equivalent

Text Solution

Verified by Experts

The correct Answer is:
B
Eq. of `NaHCO_(3)=` Eq. of `Mg(OH)_(2)`
`0.05=` equation of `Mg(OH)_(2)`
`:.` Equivalent of `Mg(OH)_(2)=0.05`
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