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In alkaline medium , KMnO(4) reacts as f...

In alkaline medium , `KMnO_(4)` reacts as follows
`2KMnO_(4)+2KOH rarr 2K_(2)MnO_(4)+H_(2)O+O`
Therefore, the equivalent mass of `KMnO_(4)` will be

A

`31.6`

B

`52.7`

C

`7.0`

D

`158.0`

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(M.M)/("Valence factor")=(158)/(1)`
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  16. 5 L of KMnO(4) solution contains 0.01 equiv. of KMnO(4). 50 ml of the ...

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