Based on the following reaction,
`XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(aq) rarr XeO_(3)(aq)+F_(2)(g)+3H_(2)O(l)` (`Delta (G)^(@)lto`)
It can be concluded that

Options

A. oxidising power of `F^(-)` is grater than that of `XeO_(6)^(4-)`
B. it is not a redox reaction
C. it is a disproportionation reaction
D. oxidising power of `XeO_(6)^(4-)` is greater than that of `F^(-)`

Answer

D

Explanation

`underset((+8))underset(uarr)(XeO_(6)^(4-))+underset((-1))underset(uarr)(F^(-) ) rarr underset((+6))underset(uarr) (XeO_(3))+underset((0))underset(uarr) (F_(2))`
Since, `DeltaG^(@)lt0`, hence it is spontaneous in forward direction. Oxidation number of `Xe` decreases, hence, it is an oxidising agent, and oxidation number of `F` increases, hence it is a reducing agent.