1 mol of `H_(3)PO_(2), H_(3)PO` and `H_(3)PO_(4)` will neutralise x mol `NaOH`, y mol of `Ca(OH)_(2)` and z mol of `Al(OH)_(2)` respectively (assuming all as strong electrolytes). x, y, z are in the ratio of:

Options

A. (a)`3:1.5:1`
B. (b)`1:2:3`
C. (c )`3:2:1`
D. (d)`1:1:1`

Answer

D

Explanation

`H_(3)PO_(2) - "monobasic" -= 1 OH^(-) -= 1 NaOH`
`H_(3)PO_(3) - "dibasic" -= 2 OH -= 1 Ca(OH)_(2)`
`H_(3)PO_(4) - "tribasic" -= 3 OH^(-) = 1 Al(OH)_(3)`