The equilibrium constant `(K_(p))` at `27^(@)C` for a homegenous gasesous reaction is `10^(-8)`. The standard free energy change `DeltaG^(@)` for the reaction is: (Use `R=2 cal K^(-1)mol^(-1)`)

Options

A. (a)`11.05 kcal`
B. (b)`-1.8 kcal`
C. (c )`-4.1454 kcal`
D. (d)`+ 4.1454 kcal`

Answer

A

Explanation

`-DeltaG^(o)=2.303 RT log K_(p)`
`=2.303xx2xx300xxlog 10^(-8)`
`:. DeltaG^(o) =11054.4 cal=11.05 kcal`