`20 ml` of an `H_2 O_2` solution on reaction with excess of acidified `KMnO_4` released `224` cc of `O_2`. What is the volume strength of that `H_2 O_2` ?

Options

A. 5.6 vol
B. 11.2 vol
C. 22.4 vol
D. 2.8 vol

Answer

A

Explanation

`2MnO_4^(-) + 5H_2 O_2 + 6H^+ rarr 2 Mn^(2+) + 5O_2 + 8 H_2O`
`22,400 "ml of" O_2 -= 34 g of H_2 O_2`
`224` ml of `O_2 -= 0.34 g of H_2 O_2`
Normality `= (0.34)/(17) xx (1000)/(20) = 1`
Volume strength `= (5.6) (N) = 5.6 Vol`.