A mixture of `CO, CO_2` and `He` on passing over red hot coke shows `40 %` increment in volume. What is the mole fraction of `CO_2` in the given mixture ?

Options

A. 0.6
B. 0.4
C. 0.2
D. 0.8

Answer

B

Explanation

`CO_2` reacts with red hot coke. Increases in volume because `CO_2` is converted into "CO".
Total volume (no. of moles) `= 100`
`:. n_(CO_2) = 40`
`:.` Mole fraction of `CO_2 = (40)/(100) = 0.4`.