`K_2 CrO_4` oxidises `KI` in the presence of `HCl` to `I_2`. The equivalent weight of the `K_2 CrO_4` is.

Options

A. `(M_w)/(2)`
B. `M_w xx (2)/(3)`
C. `(M_w)/(3)`
D. `(M_w)/(6)`

Answer

C

Explanation

`3e^- + underset(x=6)(CrO_4^(2-)) rarr underset((x=6-3=3))underset(x=3)([Cr(OH)_4]^(Theta))`
`:. E_w = (M_w)/(3)`.