`8 g` of sulphur are burnt to form `SO_(2)`, which is oxidised by `Cl_(2)` water. The solution is treated with `BaCl_(2)` solution. The amount of `BaSO_(4)` precipitated is:

Options

A. 1.0 mole
B. 0.5 mole
C. 0.75 mole
D. 0.25 mole

Answer

D

Explanation

`S overset (O_2)rarr SO_2 overset (Cl_2)rarr SO_4^(-) overset (BaCl_2)rarr BaSO_4`
One mole of `S` will give `1` mole of `BaSO_4`
Mole of `BaSO_4` formed = moles of sulphur `= (8)/(32) = (1)/(4) = 0.25`.