A body of mass m is pushed with the initial velocity `v_0` up an inclined plane set at an angle `alpha` to the horizontal. The friction coefficient is equal to k. What distance will the body cover before it stops and what work do the friction forces perform over this distance?

Explanation

Let s be the sought distance, then from the equation of increment of M.E. `DeltaT+DeltaU=A_(f r)`
`(0-1/2mv_0^2)+(+mgssin alpha)=-kmg cos alphas`
or, `s=(v_0^2)/(2g)//(sin alpha+kcos alpha)`
Hence `A_(f r)=-kmgcos alphas=(-kmv_0^2)/(2(k+tan alpha))`