Which would exhibit ionisation isomerism?

Options

A. (a) `[Cr(NH_3)_6]Cl_3`
B. (b) `[Co(NH_3)_5Br]SO_4`
C. (c) `[Cr(en)_2Cl_2]`
D. (d) `[Cr(en)_3Cl_3]`

Answer

B

Explanation

The compound which has same composition but give different ions in solution, show ionization isomerism. So
`[Co(NH_3)_5Br]SO_4` is ionization isomer.
`[CO(NH_3)_5Br]SO_4hArr[Co(NH_3)_5Br]^(2+)+SO_4^(2-)`
`[Co(NH_3)_5SO_4]Br hArr [Co(NH_3)SO_4]^+ +Br^-`