Type of isomerism which is shown by `[PtCl_2Br_2]^(2-)` is also observed in:

Options

A. (a) `[CoCl_2Br_2]^(2-)`
B. (b) `[Co(en)_3]^(3+)`
C. (c) `[PtCl_4Br_2]^(2-)`
D. (d) `[PtCl_3(NO)_2]^(2-)`

Answer

C

Explanation

Square planar `[PtCl_2Br_2]^(2-)=Show GI`
(a) Tetrahedral `[CoCl_2Br_2]^(2-)=` Does not show GI
(c) Octahedral `[PtCl_4Br_2]^(2-)=Show GI`
(d) `[PtCl_3(NO_2)]^(2-)=` This belongs to `MA_3B`, so does not show GI