Which of the following facts about the complex `[Cr(NH_3)_6]Cl_3` is wrong?

Options

A. The complex involves `d^2sp^3` hybridization and is octahedral in shape
B. The complex is paramagnetic
C. The complex is an outer orbital complex
D. The complex gives white precipitate with silver nitrate solution.

Answer

C

Explanation

`ubrace([Cr(NH_3)_6])_("Coordinate sphere") hArr ubrace(Cl_3)_("Ionisable")`
`[Cr(NH_3)_6]^(3+)+3Cl^(-)overset(AgNO_3)rarrunderset(White p recip itate)(AgCldarr)`
In `[Cr(NH_3)_6]^(3+)`, `Cr` exists as `Cr^(3+)` ion. The outer orbital electronic configuration of `Cr` is `3d^(3)4s^0`. The orbital diagram is represented by

Here, X indicates lone pair of `NH_3` donated to `Cr`. Hence,
(a) `d^2sp^3`-hybridization, octahedral. Thus, correct.
(b) There are three unpaired electrons, hence paramagnetic. Thus, correct.
(c) `d^2sp^3`-inner orbital complex, thus incorrect.
(d) Due to ionnizable `Cl^(-)` ions, white preticipate with `AgNO_3`, thus correct. Therefore, (c) is wrong.