The equation which is balanced and represents the correct product(s) is .

Options

A. (a) `Li_2O+2KClrarr2LiCl+K_2O`
B. (b) `[CoCl(NH_3)_5]^(+) + 5H^(+)rarrCO^(2+)+5NH_4^(+)+Cl^(-)`
C. (c) `[Mg(H_2O)_6]^(2+)+(EDTA)^(4-)overset(excess NaOH)rarr[Mg(EDTA)^(2+)]+6H_2O`
D. (d) `CuSO_4+4KCNrarrK_2[Cu(CN)_4]+K_2SO_4`

Answer

B

Explanation

(a) `Li_2O+2KClrarr2LiCl+K_2O`
The above equation is incorrect because amine a stronger base cannot be generated by a weaker base, `Li_2O`.
(b) `[CoCl(NH_3)_5]^(+)+ 5H^(+)rarrCO^(2+)+5NH_4^+ + O^(-4)`
The above equation is correct because amine complexes decompose under acidic medium. Thus, the complex `[CoCl(NH_3)_5]` decomposes under acidic conditions to give ammonium ions.
(c) `[Mg(H_2O)_6]^(2+)+(EDTA)^(4-)overset(excess NaOH)rarr[Mg(EDTA)^(2+)+6H_2O` The above equation is incorrect because the product formed would be `[Mg(EDTA)]^(2-)`.
(d) `CuSO_4+4KCNrarrK_2[Cu(CN)_4+K_2SO_4`
The above equation is incorrect. Thus, the correct equation is
`2KCN+CuSO_4rarrK_2SO_4+Cu+(CN)_2`
(Cyanogen gas)