Home
Class 12
PHYSICS
If two waves represented by y(1) =4 sin ...

If two waves represented by `y_(1)` =4 sin `omega`t and `y_(2)=3"sin" (omega+(pi)/(3))` interfere at a point the amplitude of the resulting wave will about

A

7

B

6

C

5

D

3.5

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • LIGHT WAVE AND INTERFERENCE OF LIGHT

    CHHAYA PUBLICATION|Exercise EXERCISE (Multiple Choice Questions ) Youngs Double Slit Experiment|19 Videos

  • LIGHT WAVE AND INTERFERENCE OF LIGHT

    CHHAYA PUBLICATION|Exercise EXERCISE (Very Short Answer Type Questions ) Waves and Wavefronts|7 Videos

  • LIGHT WAVE AND INTERFERENCE OF LIGHT

    CHHAYA PUBLICATION|Exercise EXERCISE (Multiple Choice Questions )|5 Videos

  • KIRCHHOFF'S LAWS AND ELECTRICAL MEASUREMENT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|16 Videos

  • Magnetic Properties of Materials

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos

Similar Questions

Explore conceptually related problems

The equations for displacement of two light waves forming interference pattern are y_(1) = 4 sin omega t and y_(2) =3 sin (omega t+ (pi)/(2)) . Determine the amplitude of the resultant wave.

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .

When two progressive waves y_(1) = 4 sin (2 x - 6t) and y_(2) = 3 sin (2x - 6t -(pi)/(2)) are superposed, the amplitude of the resultant wave is

When the waves y_(1) = A sin omega t and y_(2) = A cos omega t are superposed, then resultant amplitude will be

Two waves are expressed as, y_(1) = a sin omega_(1) ((x)/(c)-t) and y_(2) = a sin omega_(2) ((x)/(c)-t) Find the resultant displacement due to superposi-tion of the two waves .

x = A cos omega t + B sin omega t , the amplitude of this wire is:

Two simple harmonic motions are given by x_(1) = a sin omega t + a cos omega t and x_(2) = a sin omega t + (a)/(sqrt3) cos omega t The ratio of the amplitudes of first and second motion and the phase difference between them are respectively