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In case of a bipolar transistor beta =45...

In case of a bipolar transistor `beta` =45. The potential drop across the collector resistance of 1 k`Omega` is 5 V. The base current is approximately

A

222 `mu` A

B

55 `mu` A

C

111`mu` A

D

45 `mu` A

Text Solution

Verified by Experts

The correct Answer is:
C
Here `beta` =45
`:. I_(C)/I_(B)=45`
Now `I_(C)xx1xx10^(3)=5 " "` or `l_(C)=5xx10^(-3) =111mu` A
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