At what temperature will the r.m.s. speed of the hydrogen molecules be half of its value at `327^(@)C` ?

Options

A. `-123^(@)C`
B. `81.75^(@)C`
C. `127^(@)C`
D. `150^(@)C`

Answer

A

Explanation

`C_(2)/C_(1)=sqrt(T_(2)/T_(1))`
`thereforeC_(2)^(2)/C_(1)^(2)=T_(2)/T_(1)" "therefore1/4=T_(2)/((327+273))=T_(2)/600`
`thereforeT_(2)=150K=-123^(@)C`