Gas at a pressure `P_(0)` in contained as a vessel. If the masses of all the molecules are halved and their speeds are doubles. The resulting pressure P will be equal to

Options

A. `4P_(0)`
B. `2P_(0)`
C. `P_(0)`
D. `P_(0)/2`

Answer

B

Explanation

`P_(0)=1/3rho_(0)C^(2)andrhopropm`
`thereforeP=1/3(rho_(0)/2)(2C_(0))^(2)=1/3xxrho_(0)/2xx4C_(0)^(2)`
`thereforeP/P_(0)=(2C_(0)^(2))/(C_(0)^(2))=2/1`