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The average translational K.E. of the mo...

The average translational K.E. of the molecules in a sample of oxygen at 300K is `6xx10^(-20)J`. What is the average translational energy at 750 K?

A

`2xx10^(-19)J`

B

`1.5xx10^(-19)J`

C

`3xx10^(-18)J`

D

`3.5xx10^(-21)J`

Text Solution

Verified by Experts

The correct Answer is:
B

Average K.E. `prop "Temperature"`
`E_(2)/E_(1)=T_(2)/T_(1)=750/300=2.5`
`thereforeE_(2)=2.5xx6xx10^(-20)=1.5xx10^(-19)J`
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