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For argon, c(v)=0.075Kcal//kg//K. What i...

For argon, `c_(v)=0.075Kcal//kg//K`. What is its atomic weight? [R = 2cal/mol/k]

A

20

B

30

C

40

D

50

Text Solution

Verified by Experts

The correct Answer is:
C
Argon is monoatomic. Hence its molar specific heat at constant volume `C_(V)=3/2R=3/2xx2=3cal//mol//K`
But `c_(v)=0.075Kcal//kg//K=0.075cal//g//K`
and `C_(V)=Mc_(v)`
`thereforeM=C_(V)/c_(v)=3/0.075=40`
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