If the specific heat of a gas at constan...

If the specific heat of a gas at constant volume is `3/2R`, then the value of `gamma` will be

`5/2`

`5/3`

`5/4`

`3/5`

Text Solution

Verified by Experts

The correct Answer is:

`C_(v)=3/2RandC_(p)-C_(v)=R`
`thereforeC_(p)=C_(v)+R=3/2R+R=5/2R`
`thereforegamma=C_(p)/C_(v)=5/3`

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