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In an adiabatic change, the pressure p a...

In an adiabatic change, the pressure p and temperature T of a diatomic gas are related by the relation `ppropT^alpha`, where `alpha` equals

A

2.5

B

3.5

C

1.4

D

2.25

Text Solution

Verified by Experts

The correct Answer is:
B

For an adiabatic change `PV^(gamma)` = constant
But `V=(RT)/P" "thereforeP((RT)/P)^(gamma)="constant"`
`thereforeT^(gamma)P^(1-gamma)="Constant"`
`thereforePpropT^(gamma/(gamma-1))`
`therefore` Comparing with `PpropC^(2)`, we get `C=gamma/(gamma-1)`
For a diatomic gas, `gamma=7/5`
`thereforeC=(7/5)/(7/5-1)=7/2=3.5`
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