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An ideal gas under goes a quasi static, ...

An ideal gas under goes a quasi static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by `PV^n=constant`, then n is given by (Here `C_P and C_V` are molar specific heat at constant pressure and constant volume, respectively):

A

`n=gamma-1`

B

`n=gamma`

C

`n=gamma+1`

D

`n=1-gamma`

Text Solution

Verified by Experts

The correct Answer is:
B

`s=(dQ)/(mxxdT)` but s = 0 means dQ = 0
i.e. no heat is given or taken out from the system
i.e. the change is adiabatic
and for an adiabatic change `PV^(gamma)` = constant
But it is given that `PV^(n)` = constant
`thereforen=gamma`
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