The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by `7^@C`. The gas is `(R=8.3ml^-1Jmol^-1K^-1)`

Options

A. mixture of monoatomic and diatomic
B. monoatomic
C. diatomic
D. triatomic

Answer

C

Explanation

The work done in an adiabatic process,
`W=(nR(T_(1)-T_(2)))/(gamma-1)`
`therefore146xx10^(3)=(1000xx8.3xx7)/(gamma-1)`
`thereforegamma-1=(8.3xx7)/146=(58.1)/(146)`
`thereforegamma-1=0.4`
`thereforegamma=1.4`
`therefore` The gas is diatomic.