In a given process on an ideal gas, `dW=0` and `dQ` is negative, then for the gas:

Options

A. T will increase
B. T will decrease
C. V will increase
D. P may increase or decrease

Answer

B

Explanation

From first law of thermodynamics, dQ = dU + dW
`thereforedW=0, PdV=0" "thereforeV="constant"`
It undergoes an isochoric process
and when dW = 0, dQ = dU
and `thereforedQlt0" "thereforedUlt0`
`therefore` The themperature is decreased.