The work done during expansion of a gas in vacuum is zero, because there is

Options

A. no change in volume (`DeltaV` = 0)
B. no change in temperature
C. no change in internal energy
D. no opposing pressure (noatmospheric pressure)

Explanation

To solve the question, "The work done during the expansion of a gas in vacuum is zero, because there is," we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Work Done in Thermodynamics**:
In thermodynamics, the work done by a gas during expansion can be expressed mathematically as:
\[ W = P \Delta V \]
where \( W \) is the work done, \( P \) is the pressure exerted by the gas, and \( \Delta V \) is the change in volume.

2. **Identifying the Conditions**:
In this scenario, the gas is expanding in a vacuum. A vacuum means that there are no gas molecules present in the surrounding space, which implies that the pressure in the vacuum is zero.

3. **Applying the Formula**:
Since the pressure \( P \) in the vacuum is zero, we can substitute this into the work formula:
\[ W = 0 \times \Delta V = 0 \]
Therefore, the work done during the expansion of the gas in a vacuum is zero.

4. **Conclusion**:
The reason the work done is zero is that there is no opposing pressure against which the gas can do work. In a vacuum, there are no molecules to exert pressure, hence the gas does not perform any work during its expansion.

### Final Answer:
The work done during the expansion of a gas in vacuum is zero because there is no opposing pressure.

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