A cornot engine has the same efficiency between (i) 100 K and 500 K and (ii) T and 900 K. Find T.

Options

A. 130 K
B. 160 K
C. 180 K
D. 200 K

Answer

C

Explanation

`eta=1-T_(2)/T_(1)`
For the same efficiency, the ratio `T_(2)/T_(1)` must be equal in both the cases.
`therefore100/500=T/900" "thereforeT/900=1/5`
`thereforeT=180K`