The temperature inside and outside a refrigerator are 273 K and 300 K respectively. Assuming that the refrigerator cycle is reversible. For every joule of work done heat delivered to the surrounding will be nearly :-

Options

A. 5 J
B. 7 J
C. 9 J
D. 12 J

Answer

C

Explanation

`beta=Q_(2)/W=T_(2)/(T_(1)-T_(2))`
`=273/(303-273)=273/30`
`Q_(2)=WxxB=1xx273/30=9.1=9J`
(Heat is expressed in work units.)