For a carnot engine the source and the sink temperatures are `527^(@)C and 47^(@)C` respectively and the engine extracts 800 J of heat in each cycle. What is the area enclosed by the P-V diagram in terms of energy units ?

Options

A. 480 J
B. 600 J
C. 350 J
D. 280 J

Answer

A

Explanation

`T_(1)=273+527=800K` = Temperature of the source
`T_(2)=273+47=320K` = Temperature of the sink
`thereforeeta=(T_(1)-T_(2))/T_(1)=(800-320)/800=480/800=3/5`
`thereforeeta=W/Q" "thereforeW=etaQ=3/5xx800=480J`
But the work done in each cycle
= area enclosed by the P-V diagram
= 480 J (in terms of energy units)