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The temperature of a black body is incre...

The temperature of a black body is increased from `7^(@)C` to `567^(@)C`, then the rate of energy radiation becomes

A

3 times

B

27 times

C

9 times

D

81 times

Text Solution

Verified by Experts

The correct Answer is:
D
`R_(2)/R_(1)=((567+273)^(4))/((7+273)^(4))=(840)^(4)/(280)^(4)=3^(4)=81`
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MARVEL PUBLICATION-KINETIC THEORY OF GASES ,THERMODYNAMICS AND RADIATION-TEST YOUR GRASP - 9
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