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The ratio of energy of emitted radiation...

The ratio of energy of emitted radiation of black body at ` 27^(@)C and 927^(@) c` is

A

`1 : 4`

B

`1 : 16`

C

`1 : 256`

D

`1 : 64`

Text Solution

Verified by Experts

The correct Answer is:
C
`Q_(1)/Q_(2)=(T_(1)/T_(2))^(4)=(300/1200)^(4)=1/256`
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MARVEL PUBLICATION-KINETIC THEORY OF GASES ,THERMODYNAMICS AND RADIATION-TEST YOUR GRASP - 9
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