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At what temperature, a perfectly black b...

At what temperature, a perfectly black body would radiate energy at a rate of `90.72xx10^(4)W//m^(2)` ?

A

1500 K

B

1800 K

C

2000 K

D

2500 K

Text Solution

Verified by Experts

The correct Answer is:
C
By Stefan's law, `E = sigmaT^(4)`
`thereforeT=(E/sigma)^(1//4)=[(90.72xx10^(4))/(5.67xx10^(-8))]^(1//4)`
`=(16xx10^(12))^(1//4)=2000K`
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