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A spherical black body with a radius of 12 cm radiates 450 W power at 500 K. What would be the power of radiation if radius were to be halved and the temperature is doubled ?

A

1800 W

B

2000 W

C

1500 W

D

1200 W

Text Solution

Verified by Experts

The correct Answer is:
A

Energy radiated/sec = Radiated Power
`E=AsigmaT^(4)=(4piR^(2))sigmaT^(4)" "`(Stefan's law)
In the second case, `R'=R/2andT'=2T`
`thereforeE'=4pi(R/2)^(2)xxsigmaxx(2T)^(4)`
`=4piR^(2)xxsigmaT^(4)(1/4xx16)=4E`
`thereforeE'=4xx450=1800W`
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