Heat energy absorbed by a system in going through a cyclic process shown in figure is

Options

A. `10^(-3) piJ`
B. `10^(2) piJ`
C. `10^(3) piJ`
D. `10^(4) piJ`

Answer

B

Explanation

dQ = dU + dW
In a cyclic process, dU = 0
`therefore` dQ = dW = Area of the (P - V) diagram
= Area of the circle
`=pir^(2)=pi(20/2)^(2)KPaxx"litre"`
`" "[1KPa=10^(3)Pa,1"litre"=10^(3)c c`
`" "=10^(3)xx10^(-6)m^(3)=10^(-3)m^(3)]`
`=100pixx10^(3)xx10^(-3)J`
`=100piJ`
`thereforedQ=10^(2)piJ`